### python

#### Formatting string to certain character limit in Python

```I have a code that outputs a whole bunch of numbers after doing some maths on them. At one point in the code they are rounded off with numpy.rint, and in certain cases (I believe when a 9 is rounded to a 10) I end up with a trailing zero that I do not want. I have some code that looks sort-of like this
ra3n = ra3/60 * 10
ra3n = np.rint(ra3n)
ra3n = ra3n.astype(str) ##there is a good reason that this needs to be a string
I need all of the resulting ra3n to be 5 characters long, but occasionally one pops out as 6 characters long. How would I format this properly? Keep in mind I'm a total python noob, so I might need it spelled out for me =)
EDIT:
Here's my output:
00244-2451
00244-2702
00278-0629
00286-1614
00295-1101
002910-0546
00303+0711
00305+2246
00348+2604
003410+0423
00355-0204
00359+1236
00360-0931
00386-1210
The instances where there are six digits instead of 5 in the first half of the string are the erroneous ones; those trailing zeroes should not be there.
```
```ra3n = ra3n[:-1] if ra3n[-1] == '0' else ra3n
There's probably a better solution, but I'm not sure I really understand your issue without seeing some output.
```
```You change the type of ra3n, which is poor programming practice. Try this.
ra3n = format(ra3/60.*10., '5f')[:5]
This gives exactly five characters. Note that if the string would usually be six characters long, this cuts off the last character, for good or for bad. Note also that I included decimal points in the 60 and 10 numbers: this guarantees that floating-point division will be used, rather than integer division if this is done in Python 2.```

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