How do I use SQLalchemy to treat an existing select object as a view?
I have a select object s1 and I would like to treat it as a view, so that I can join other tables onto it. I have tried something like this: s1 = select([t1], ...) s2 = s1.join(t2, t1.c.id==t2.c.id) but I get an error: sqlalchemy.exc.StatementError: Not an executable clause I have tried this: s1 = select([t1], ...) s2 = select([t1, t2], from_obj=s1.alias().join(t2, t1.c.id==t2.c.id)) but I get this error: sqlalchemy.exc.ProgrammingError: (ProgrammingError) invalid reference to FROM-clause entry for table "t1" The reason I need to do this is because s1 is returned from a function that applies a complex where clause and I'd rather not rebuild that where clause when constructing s2.
substitute unicode strings using re
Python : Fire off AJAX with feedparser
Python Pandas - Odds Ratio with Scipy (P Value = 0?)
Vim Pymode not working with matplotlib
Downloading Excel files with Django and Angular2
Get length of Azure queue from Python via REST API
window shrinks when label is packed, even though textbox is bigger
How to use random.sample() that it always generate number
CX_Oracle for python, under Anaconda is not installing
Pynput keylogger will record characters in explorer and on desktop but will return backspace in chrome
pygame is not responding after playing an audio file
In Python 2.7, how can I return calculations without defining variables in the constructor?
Python: create a new dictionary getting values from a dictionary of nested list
Values from subroutine not being returned/refreshed python
Proper way to relative import in Python 2.7
How to elegantly create matrix with row and column indices as first row / column?